-32x^2+22500x=0

Solution for -32x^2+22500x=0 equation:

-32x^2+22500x=0

a = -32; b = 22500; c = 0;
Δ = b2-4ac
Δ = 225002-4·(-32)·0
Δ = 506250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{506250000}=22500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22500)-22500}{2*-32}=\frac{-45000}{-64}
=703+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22500)+22500}{2*-32}=\frac{0}{-64}
=0
$